java sm3加密

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java sm3加密是什么？讓我們一起來了解一下吧！

java sm3加密是一種加密算法。Sm3算法是我國自己設計的哈希算法，在商用密碼體系當中，sm3算法的作用主要是數字簽名及驗證、消息認證、隨機數產生等。Sm3算法是公開的，進行加密會產生一個32字節的值。

Sm3算法的運行過程如下：

1.填充：使填充后的數據的長度是512的整數倍

2.進行分組：把填充后的信息按照512比特一個分組進行分組。

3.迭代壓縮得到最后的哈希值：如果信息分為N組，那么IV（N）就是最后得到的雜湊值。

java中采用sm3算法加密代碼如下：

public?class?SM3?{
?
????public?static?final?byte[]?iv?=?{?0x73,?(byte)?0x80,?0x16,?0x6f,?0x49,
????????????0x14,?(byte)?0xb2,?(byte)?0xb9,?0x17,?0x24,?0x42,?(byte)?0xd7,
????????????(byte)?0xda,?(byte)?0x8a,?0x06,?0x00,?(byte)?0xa9,?0x6f,?0x30,
????????????(byte)?0xbc,?(byte)?0x16,?0x31,?0x38,?(byte)?0xaa,?(byte)?0xe3,
????????????(byte)?0x8d,?(byte)?0xee,?0x4d,?(byte)?0xb0,?(byte)?0xfb,?0x0e,
????????????0x4e?};
?
????public?static?int[]?Tj?=?new?int[64];
?
????static
????{
????????for?(int?i?=?0;?i?=?0?&&?j?=?0?&&?j?<=?15)
????????{
????????????return?GG1j(X,?Y,?Z);
????????}
????????else
????????{
????????????return?GG2j(X,?Y,?Z);
????????}
????}
?
????//?邏輯位運算函數
????private?static?int?FF1j(int?X,?int?Y,?int?Z)
????{
????????int?tmp?=?X?^?Y?^?Z;
????????return?tmp;
????}
?
????private?static?int?FF2j(int?X,?int?Y,?int?Z)
????{
????????int?tmp?=?((X?&?Y)?|?(X?&?Z)?|?(Y?&?Z));
????????return?tmp;
????}
?
????private?static?int?GG1j(int?X,?int?Y,?int?Z)
????{
????????int?tmp?=?X?^?Y?^?Z;
????????return?tmp;
????}
?
????private?static?int?GG2j(int?X,?int?Y,?int?Z)
????{
????????int?tmp?=?(X?&?Y)?|?(~X?&?Z);
????????return?tmp;
????}
?
????private?static?int?P0(int?X)
????{
????????int?y?=?rotateLeft(X,?9);
????????y?=?bitCycleLeft(X,?9);
????????int?z?=?rotateLeft(X,?17);
????????z?=?bitCycleLeft(X,?17);
????????int?t?=?X?^?y?^?z;
????????return?t;
????}
?
????private?static?int?P1(int?X)
????{
????????int?t?=?X?^?bitCycleLeft(X,?15)?^?bitCycleLeft(X,?23);
????????return?t;
????}
?
????/**
?????*?對最后一個分組字節數據padding
?????*
?????*?@param?in
?????*?@param?bLen
?????*????????????分組個數
?????*?@return
?????*/
????public?static?byte[]?padding(byte[]?in,?int?bLen)
????{
????????int?k?=?448?-?(8?*?in.length?+?1)?%?512;
????????if?(k?>?(32?-?n));
????}
?
????private?static?int?bitCycleLeft(int?n,?int?bitLen)
????{
????????bitLen?%=?32;
????????byte[]?tmp?=?bigEndianIntToByte(n);
????????int?byteLen?=?bitLen?/?8;
????????int?len?=?bitLen?%?8;
????????if?(byteLen?>?0)
????????{
????????????tmp?=?byteCycleLeft(tmp,?byteLen);
????????}
?
????????if?(len?>?0)
????????{
????????????tmp?=?bitSmall8CycleLeft(tmp,?len);
????????}
?
????????return?bigEndianByteToInt(tmp);
????}
?
????private?static?byte[]?bitSmall8CycleLeft(byte[]?in,?int?len)
????{
????????byte[]?tmp?=?new?byte[in.length];
????????int?t1,?t2,?t3;
????????for?(int?i?=?0;?i?>?(8?-?len));
????????????t3?=?(byte)?(t1?|?t2);
????????????tmp[i]?=?(byte)?t3;
????????}
?
????????return?tmp;
????}
?
????private?static?byte[]?byteCycleLeft(byte[]?in,?int?byteLen)
????{
????????byte[]?tmp?=?new?byte[in.length];
????????System.arraycopy(in,?byteLen,?tmp,?0,?in.length?-?byteLen);
????????System.arraycopy(in,?0,?tmp,?in.length?-?byteLen,?byteLen);
????????return?tmp;
????}
?
????/*private?static?void?print(int[]?arr)
????{
????????for?(int?i?=?0;?i?
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